Direction: A truss is shown in the figure. Members are to equal cross section A and same modulus of elasticity E. A vertical force P is applied at point C.
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Force in the member AB of the truss is
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- P/√2
- P/√3
- P/2
- P
Correct Option: C
(Method of joints)
∑ Fx = 0
FBD cos θ + FAB = 0
∑ Fy = 0
| FBD sin θ + | = 0 | 2 |
| + | + FAB = 0 | |||
| √2 | √2 |
| ∴ FAB = | 2 |
