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A block of mass M is released from point P on a rough inclined plane with inclination angle θ, shown in the figure below. The coefficient of friction is μ. If μ < tan θ, then the time taken by the block to reach another point Q on the inclined plane, where PQ = s, is
Correct Option: A
Mg sin θ – μ Mg cos θ= Ma
⇒ a = g sin θ – μ g cos θ
Now s = ut + | at2 | 2 |
But u = 0