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A block weighing 981 N is resting on a horizontal surface. The coefficient of friction between the block and the horizontal surface is μ = 0.2. A vertical cable attached to the block provides partial support as shown. A man can pull horizontally with a force of 100 N. What will be the tension, T (in N) in the cable if the man is just able to move the block to the right?
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- 176.2
- 196.0
- 481.0
- 981.0
Correct Option: C
Net normal force on block
N = W – T
= 981 – T
Frictional force,f = μN
Under equilibrium, i.e. when man is just able to move the block
μN = 100
⇒ μ(981–T) = 100
⇒ 0.2 (981 – T) = 100
| T = - | + 981 | 0.2 |
= 981 – 500 = 481N
