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Two books of mass 1 kg each are kept on a table, one over the other. The coefficient of friction on every pair of contacting surfaces is 0.3. The lower book is pulled with a horizontal force F. The minimum value of F for which slip occurs between the two books is
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- zero
- 11.77 N
- 5.88 N
- 8.83 N
Correct Option: B
[amax]A = ?
[amax]A → [(fs)max]AB
A → 3N
[(fx)max]AB = μsNAB
= 0.3 × 9.81 = 2.943 N
| (aA)max = | = 2.943 m/s2 | mA |
At that condition,
Fmin – 8.829 = mB aB
Fmin = 8.829 + 1 × 2.943
Fmin = 11.772 N
