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A cylinder of 25 mm diameter and 100 mm length is turned with a tool, for which the relation VT0.25 = 55 is applicable. The cutting velocity is 22 m/min. For a tool feed of 0.046 mm/rev, the number of tool regrinds required to produce 425 cylinders is
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- 12
- 22
- 43
- 85
Correct Option: D
D = 25 mm,
h = 100 mm
VT0.25 = 55
V = 22 m/min, f = 0.046 mm/ rev
| V = | , N = | ||
| 60 | π × 25 |
N = 280r/mm
| time/piece = | = | = 7.76 min | ||
| fN | 0.046 × 280 |
425 piece time = 425 × 7.76 = 3299.7 min
| one tool life T = |  |  | 1/0.25 = | | | 9 = 39 | ||
| V | 22 |
| ⇒ - 10 = y + | ||
| 10 |
| No. of tool Regrinding = | = 85 | |
| 39 |
