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The rake angle of a cutting tool is 15°, shear angle 45° and cutting velocity 35 m/min. What is the velocity of chip along the tool face?
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- 28.5 m/min
- 27.3 m/min
- 25.3 m/min
- 23.5 m/min
Correct Option: A
α = 15°
φ = 45°
V = 35 m/min
= | = | |||
cos(φ-α) | sinφ | cos α |
V = | = | ||
cos(φ-α) | cos(45 - 10) |
Vc = 25.58m/min