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An elevator (lift) consists of the elevator cage and a counter weight, of mass m Chain each. The cage and the counter weight are connected by chain that passes over a Cage pulley. The pulley is coupled Counter weight to a motor. It is desired that the elevator should have a maximum stopping time of seconds from a peak speed v. If the inertias of the pulley and the chain are neglected, the minimum power that the motor must have is
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1 mv² 2 -
mv² 2t -
mv² t -
2mv² t
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Correct Option: C
Power = dW / dt (rate of doing work or rate of change of K.E. energy of the system)
Initial Kinetic energy of the system
= | = mv² + | mv² = mv² | 2 | 2 |
Final Kinetic energy = 0
Time duration it occurs = t
⇒ Power = | t |