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A stone with mass of 0.1 kg is catapulted as shown in the figure. The total force Fx (in N) exerted by the rubber band as a function of distance x (in m) is given by Fx = 300x2. If the store is displaced by 0.1 m from the un-stretched position (x = 0) of the rubber band, the energy stored in the rubber band is
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- 0.01 J
- 0.1 J
- 1 J
- 10 J
Correct Option: B
Energy stored in the bar
= Work done by the stone
= 300 × | 3 |
= 100 × 0.13
= 0.1J