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An annular disc has a mass m, inner radius R and outer radius 2R. The disc rolls on a flat surface without slipping. If the velocity of the center of mass is v, the kinetic energy of the disc is
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- 9/16 mv2
- 11/16 mv2
- 13/16 mv2
- 15/16 mv2
Correct Option: C
I = | 2 |
K.E. = (K.E.) translation + (K.E.) Rotation
= | mv² + | Iω² | 2 | 2 |
Where V = 2 R ω
⇒ ω = | 2R |
∴ K.E. = | mv² + | 2 | 16 |
K.F. = | 16 |