For a typical sample of ambient air (at 30°C, 75% relative

For a typical sample of ambient air (at 30°C, 75% relative humidity and standard atmospheric pressure), the amount of moisture in kg per kg of dry air will be approximately.

Given data:
Dry bulb temperature:
T_db = 35°C
Relative humidity
φ = 75° = 0.75
At 35°C, P_s = .05628 bar

φ =		P_v	⇒ 0.75 =	P_v
		P_s		.05628

P_v = 0.75× .05628 =.04221 bar
Specific humidity,

ω =		.622P_v	=	.622 × .04221
		P - P_v		1.0135 - .04221

= 0.0270 kg/kg of dry air.