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If the input X3 X2 X1 X0 to the ROM shown below are 8-4-2-1 BCD numbers, then output Y3Y2Y1Y0 are—
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- gray code number
- 2-4-2-1 BCD number
- excess 3 code converter
- none of the above
Correct Option: C
In the given figure
Y3 = (D6, D7, D8, D9)
Y2 = (D4, D5, D6, D7, D8)
Y1 = (D2, D3, D8, D9)
Y0 = (D1, D3, D5, D7, D9)
For any input say | Outputs | |
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X3 X2 X1 X0 | Y3 Y2 Y1 Y0 | |
(i) 1 0 0 1 | we get | 1 1 1 1 |
(ii) 0 1 1 1 | we get | 1 1 0 1 |
(iii) 0 1 1 1 | we get | 1 1 0 0 |
which is equivalent to 2–4–2–1 BCD number.
Hence alternative (B) is the correct choice.