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  1. The transfer function of a system is 10/1 + s. When operated as a unity feedback system, the steady state error to a unit step input will be—
    1. zero
    2. – 9
    3. 10
    4. infinity
Correct Option: B

T.F. =
C(s)
=
10
and H(s) = 1
R(s)1 + s

G(s)
=
10
1 + G(s)H(s)1 + s

G(s)
=
10
1 + G(s).11 + s

G(s) + SG(s) = 10 + 10 G(s)
G (s) [1 + s – 10] = 10
G(s) =
10
s - 9

Also, we know that,
E(s)
=
1
R(s)1 + G(s) H(s)

or
E(s) =
R(s)
{1/s for unit step or}
1 + G(s) H(s)

E(s) =
1/s
1 + 10/s - 9.1

or
E(s) =
(s - 9)
(s + 1).s

Now,
ess = s → 0Lim sE(s) = s → 0Lim
s·(s – 9)
=
– 9
= -9
(s + 1).s1



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