Correct Option: C

From given figure

	6	= 20
	log ω1 – log10 10

or
log ω₁ – 1 = 6/20
or
log ω₁ = 0·3 + 1
or
log ω₁ = 1·3
or
ω₁ = 10^1·3
or
ω₁ = 19·95 ≈ 20

and	6	= 20
	log 10ω – logω1

or	26	= 20
	log ω – log20

or log ω – 1·3 = 26/20 = 1·3
or
log ω = 2·6
or
ω = 102·6 = 400
Hence alternative (C) is the correct choice.