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If the unit step response of a network is (1 – e–αt), then its unit impulse response will be—
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- α e–αt
- α e–t/α
- 1/α e–αt
- (1 – α) e–αt
- α e–αt
Correct Option: A
Given the unit step response is 1– e–αt, means
If r(t) = u(t)
then
R(s) = 1/s
y(t) = 1 – e–αt then
Y(s) = 1/s – 1/s + α = α/s(s + α)
Therefore, the transfer function of the system,
H(s) = | |
R(s) |
= | |
s(s + α) 1/s |
= | |
s + α |
Now, for input, r(t) = δ (t)
i.e., R(s) = 1
Y(s) = H(s) R(s)
or
Y(s) = | ·1 | |
s + α |
or
Y(t) = α·e–αt
Alternative method: Unit impulse response of a linear, time invariant network is the derivative of unit step function response of the network. Unit step response is (1 – e–αt)
∴ Unit impulse response is – (– α) e–αt = αe–αt