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  1. In the network shown in the given figure. If the voltage V at the time considered is 20 V, then dV/dt at that time will be—


    1. 1 V/s
    2. 2 V/s
    3. – 2 V/s
    4. Zero
Correct Option: B

From figure, the current through
20Ω resistor = 20/20 = 1A.
current through 10Ω resistor
= 40 – 20/10 = 2A.
By applying KCL at point A, current in the capacitor, say
i = 2 – 1 = 1A.
As we know that current across capacitor is given by relation

i = C
dV
dt

i =
1
dV
2dt

or
or
dV
= 2V/s
dt



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