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In the network shown in the given figure. If the voltage V at the time considered is 20 V, then dV/dt at that time will be—
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- 1 V/s
- 2 V/s
- – 2 V/s
- Zero
- 1 V/s
Correct Option: B
From figure, the current through
20Ω resistor = 20/20 = 1A.
current through 10Ω resistor
= 40 – 20/10 = 2A.
By applying KCL at point A, current in the capacitor, say
i = 2 – 1 = 1A.
As we know that current across capacitor is given by relation
i = C | |
dt |
i = | ||
2 | dt |
or
or | = 2V/s | |
dt |
