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A linear stable invariant system is forced with an input given below
x (t) = A sin ωt
x (t)⎯→ [G (s) ]⎯→y (t)
Under steady-state conditions, the output y (t) of the system will be—
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- A sin (ωt + φ), where φ = tan– 1 |G (jω)|
- | G (jω) | A sin [ωt + < G (jω)]
- | G (jω) | A sin [2ωt + < G (jω)]
- AG (jω) sin [ωt + G (jω)]
- A sin (ωt + φ), where φ = tan– 1 |G (jω)|
Correct Option: B
Given x(t) ⎯→ [G(s)] ⎯→ y(t)
x(t) = A sin ωt
steady state response
Y(jω) = X(jω) .G(jω)
where, X(jω) = A ∠sin ωt
G(jω) = |G(jω)| < G(jω)
or
Y(t) = A sin [ωt + < G(jω)].|G(jω)|
or
y(t) = A|G(jω)| sin [ωt + < G(jω)]
