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For the circuit shown below, the current Ix and power delivered by the independent source is—
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- 0·4A, 16W
- – 0·4A, – 16W
- 4A, 160W
- – 4A, – 160W
- 0·4A, 16W
Correct Option: B
The given circuit
Apply KCL at node A
| 2Ix + | = Ix | |
| (400 + 200)Ω |
or
| Ix = - | |
| 600 |
From figure
| Ix = | |
| 500 |
From equation (i) and (ii)
| = | ||
| 600 | 500 |
or
– 5VA = 240 – 6VA
or
VA = 240V
and
| Ix = | = | = – 0·4A | ||
| 600 | 600 |
Power delivered by the independent source is
= 40 × Ix = 40 × (– 0·4) = – 16 W.
