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The circuit shown in figure below is equivalent to a load of—
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4 Ω 3
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8 Ω 3 - 4Ω
- 2Ω
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Correct Option: B
The given circuit
The load is given by ratio of voltage, V to the current, I
V = 4 (I – I1) …(i)
and
V = 2I1 + 2I …(ii)
From equation (i) and (ii):
4I – 4I1 = 2I1 + 2I
or
2I = 6I1
or
I = 3I1
or
I1 = I/3
Now,
V = 4 | ![]() | I - | ![]() | = | ||
3 | 3 |
or
= | Ω | ||
I | 3 |
Hence alternative (B) is the correct choice.