-
In figure, the value of R is—
-
- 10Ω
- 18Ω
- 24Ω
- 12Ω
- 10Ω
Correct Option: A
The given circuit: 
Applying KCL at node C,
| = | + | + | = 0 | |||
| 14 | 1 | 2 |
or
| Vc | ![]() | + | + | ![]() | = | + | = | + | |||||||
| 14 | 1 | 2 | 14 | 1 | 14 | 1 |
or
| Vc | ![]() | ![]() | = | ||
| 14 | 14 |
or
VC = 30V
Now, current in 14Ω resistor,
| I14Ω = | = | ||
| 14 | 14 |
= 5A
So,
IR = 10 – 5 = 5A
and
| R = | = | ||
| IR | 5 |
or
R = 60/5 ≈ 12Ω
Hence alternative (D) is most correct choice.

