-
In figure, the value of R is—
-
- 10Ω
- 18Ω
- 24Ω
- 12Ω
- 10Ω
Correct Option: A
The given circuit:
Applying KCL at node C,
= | + | + | = 0 | |||
14 | 1 | 2 |
or
Vc | ![]() | + | + | ![]() | = | + | = | + | |||||||
14 | 1 | 2 | 14 | 1 | 14 | 1 |
or
Vc | ![]() | ![]() | = | ||
14 | 14 |
or
VC = 30V
Now, current in 14Ω resistor,
I14Ω = | = | ||
14 | 14 |
= 5A
So,
IR = 10 – 5 = 5A
and
R = | = | ||
IR | 5 |
or
R = 60/5 ≈ 12Ω
Hence alternative (D) is most correct choice.