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  1. Assuming ideal elements in the circuit shown below, the voltage Vab will be—


    1. – 3V
    2. 0V
    3. 3V
    4. 5V
Correct Option: A

The given circuit:

Applying KVL in the loop, we get,
Vab – 2 × 1 + 5 = 0
or
Vab = 2 – 5
= – 3V.



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