-
The circuit shown in figure 1 is replaced by that in figure 2. If current ‘I’ remains the same, then R0 will be—
-
- Zero
- R
- 2R
- 4R
- Zero
Correct Option: D
The given circuit: 
In order to make current-I same in both figures:
| = | + R0 | ||
| 1/32R + 1/16R + 1/8R | 1/4R + 1/2R + 1/R |
or
| = | + R0 | ||
| 7 | 7 |
or
| R0 = | - | = | |||
| 7 | 7 | 7 |
or
R0 = 4R
