Correct Option: A

The given circuit

Applying KCL at node A

V1 - 20	+	V1 - 0.5V1 - V2	= 2
20		5

or

V1		1	+	1		-	V2	= 3
		20		10			5

or

3V1	-	V2	= 3
20		5

or
3V₁ – 4V₂ = 60 . . . . . . …(i)
KCL at node B

V2 - V1 + 0.5V1	+	V2	+	V2 - 40	= 4
5		2		10

V2		1	+	1	+	1		-	V1	= 8
		5		2		10			10

or

V2		2 + 5 + 1		-	V1	= 8
		10			8

or
8V₁ – V₁ = 80 …. . . (ii)
From equation (i) and (ii)
V₁ = 40V and V₂ = 15V
Hence alternative (A) is the correct choice.