For the circuit shown in the figure, the Thevenin voltage

For the circuit shown in the figure, the Thevenin voltage and resistance looking into X–Y are—

The given circuit:

V_th Calculation:

From above figure: V_A = V_th
KCL at node A

V_A	+	V_A – 2i	+	V_A	= 2
1		1		2

Also,

i =	V_A	= V_A
	1

Now,

V_A +	V_A – 2V_A	+	V_A	= 2
	1		2

or
V_A = V_th = 4V
ISC Calculation:

From above figure,
I_SC = 2A
Now,

R_th =	V_th	=	V_OC	=	4V	= 2Ω
	I_SC		I_SC		2A

Hence alternative (D) is the correct choice.