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The causal systems is/are—
(i) y(n) = x2(n) u(n)
(ii) y(n) = x(|n|)
(iii) y(n) = x(n) – x(n2 – n)N (iv) y(n) = ∑ x(n – k) k = 1
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- (i), (ii) and (iii)
- (i) and (iv)
- (iii) and (iv)
- (i) and (iv)
Correct Option: D
Given
(i) y(n) = x2(n) u(n)
This system is causal for any value of n.
(ii) y(n) = x(|n|) If we put any negative value of n, say n = – 2, we get
y(– 2) = x(|– 2|) = x(2)
i.e., output depends on the future value of input.
Hence, this system is non-causal.
(iii) y(n) = x(n) – x(n2 – n)
This system is causal for n = 1, 2 and non-causal for values other than 0, 1 and 2.
Let n = 3, we get
y(3) = x(3) – x(32 – 3)
y(3) = x(3) – x(6)
which is non-causal
N | ||
(iv) y(n) = | ∑ | x(n – k) |
k = 1 |
Since, the limit of k is positive, therefore, this system is causal for any value of k.
Hence, alternative (D) is the correct choice.