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The Fourier transform of a double-sided exponential signal x(t) = e– b|t|
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2b b2 + ω2 -
e– j tan– 1 bt ω - does not exist
- exists only when it is single sided
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Correct Option: A
Fourier transform of signal x(t) is given as
x(jω) = ∫∞– ∞ x(t) e– jωt dt
or x(jω) = ∫∞– ∞ e– b|t| .e– jωt dt
x(jω) = ∫0– ∞ ebt.e– jωt dt + ∫∞0 ebt.e– jωt dt
or x(jω) = | ![]() | ![]() | 0 | + | ![]() | ![]() | ∞ | ||
b – jω | – ∞ | – (b + jω) | 0 |
or x(jω) = | + | |||
b – jω | jω + b |
or x(jω) = | b2 + ω2 |
Hence, alternative (A) is the correct choice.