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The spectral density of a random signal is given by π[δ(ω – ω0) + δ(ω + ω0)]. The auto-correlation function of the signal is—
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- cos ω0τ
- sin ω0τ
- cos [(ω – ω0)τ]
- sin [(ω – ω0)τ]
Correct Option: A
We know that spectral density of is the Fourier transform of autocorrelation function.
Let the autocorrelation function Rxx.
(A) Rxx(τ) = cos ω0τ
Rxx(τ) = | 2 |
or Sxx(ω) = ∫∞– ∞ Rxx e– jωτdτ
or Sxx(ω) = ∫∞– ∞ | ![]() | ![]() | e– jωτdτ | 2 |
or Sxx(ω) = π[δ(ω – ω0) + δ(ω + ω0)]
(by using frequency shifting property)
There, no need to solve other alternative. This is the correct answer.