-
Which of the following is the inverse z-transform of
X(z) = z |z| < 2 (z – 2) (z – 3)
-
- [2n – 3n] u(– n – 1)
- [3n – 2n] u(– n – 1)
- [2n – 3n] u(n + 1)
- [2n – 3n] u(n)
Correct Option: A
Given that
X(z) = | |z| < 2 | (z – 2) (z – 3) |
or | = | + | ||||
z | z – 2 | z – 3 |
or | = | + | ||||
z | z – 2 | z – 3 |
or X(z) = – | ![]() | ![]() | + | ![]() | ![]() | ||
z – 2 | z – 3 |
or X(z) = – | ![]() | ![]() | + | ![]() | ![]() | ||
1 – 2z– 1 | 1 – 3z– 1 |
Now, since in the region |z| < 2 both the poles are exterior i.e., anti-causal and hence inverse z-transform.
x(n) = [– (– 2n) + (– 3n)] u(– n – 1)
or x(n) = (2n – 3n) u(– n – 1)
Hence, alternative (A) is the correct choice.