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The Laplace transform of the given figure will be—
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1 + e– sT s -
1 – e– sT s -
1 [1 – e– sT] s -
1 [1 + e sT ] s
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Correct Option: C
F(s) = L{f(t)} = ∫∞0 f(t)e– stdt
= ∫T0 1·e– st dt
= | ![]() | ![]() | – T | |
s | 0 |
= | [e– sT – 1] | s |
= | [1 – e– sT] | s |
Alternative method:
The given pulse is represented in terms of the step functions as
f(t) = u(t) – u(t – T)
L{f(t)} = | – | e– st | ||
s | s |
= | [1 – e– sT] | s |
Hence, alternative (C) is the correct choice.