-
For n < 0, there is no overlap between the non-zero postions of x[k] and h[n – k] and consequently, y[n] has a value equal to—
-
- 1
- – 1
- 0
- ± 1
Correct Option: C
y(n) = | ![]() | x(k) x[n – k] |
i.e., convolution of two sequence x[ n] and x[ n] then loss if there is no overlap between the non-zero portion of x[ k] and x[n – 1] then y (1) will be zero.