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Signal and systems miscellaneous

Signals and Systems

  1. System described by differential equation—
    (i)
    d
    y(t) + 2y(t) = x(t)
    dt

    (ii)
    d
    y(t) + y(t) + 4 = x(t)
    dt
    1. (i) is linear but (ii) is non-linear
    2. (i) is non-linear but (ii) is linear
    3. both (i) and (ii) are linear
    4. both (i) and (ii) are non-linear
Correct Option: A

(i) Let the response of the system to x1(t) be y1(t) and the response of the system to x2(t) be y2(t).
Thus, for the input x1(t) the describing equation is

dy1(t)
+ 2y1(t) = x1(t) = F[y1(t)]
dt

and for the input
dy2(t)
+ 2y2(t) = x2(t) = F[y2(t)]
dt

Multiplying these equations by a1 and a2 respectively, and adding yields,
a1
dy1(t)
+ a2
dy2(t)
+ 2a1y1(t) + 2a2y2(t) = a1x1(t) + a2x2(t)
dtdt

d
[a1y1(t) + a2y2(t)] + 2 [a1y1(t) + a2y2(t)] = a1x1(t) + a2x2(t)
dt

i.e., F[y1(t)] + F[y2(t)] = F[y1(t) + y2(t)]
Hence, the system is linear. (ii) Similarly, for equation
d
y(t) + 4 = x(t)
dt

dy1(t)
+ y1(t) + 4 = x1(t) = F[y1(t)]
dt

and for input x2(t).
Multiplying these equations by a1 and a2 respectively, and adding yields,
dy2(t)
+ y2(t) + 4 = x2(t) = F[y2(t)]
dt

i.e.,
d
+ [a1y1(t) + a2y2(t)] + 2 [a1y1(t) + a2y2(t)] + 4(a1 + a2) ≠ a1.x1(t) + a2.x2(t)
dt

i.e., F[y1(t)] + F[y2(t)] ≠ F[y1(t) + y2(t)]
Hence, the system is non-linear.
Therefore, alternative (A) is the correct choice.



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