Correct Option: B

We will apply same approach as discussed in above problem.

(A)			1		n	+ n		1		n		u(n)
			2					2

∴		1		n	←z→		1
		2					1 -	1	z-1
								2

and n		1		n	←z→		z-1
		2						1 -	1	z-1		2
									2

Now,			1		n	+ n		1		n		u(n)
			2					2

=	1				+	z-1
	1 -	1	z-1				1 -	1	z-1		2
		2						2

=	1 –	1	z– 1	+ z– 1
		2
		1 –	1	z– 1		2
			2

=	1 +	1	z– 1
		2
		1 –	1	z– 1		2
			2

Since, (A) is not the correct choice, so we will solve for next option, i.e., (B).

			1		n	+	n		1		n		u[n]
			2				2		2

↔	1				+		z-1
	1 -	1	z-1			2		1 -	1	z-1		2
		2							2

↔		1 –	1	z– 1		+ z– 1
			2
		1 –	1	z– 1		2
			2

↔		2 – z– 1 + z– 1
	2		1 -	1	z-1		2
				2

↔		2
	2		1 -	1	z-1		2
				2

↔		1
			1 -	1	z-1		2
				2

Therefore, option (B) is the correct choice.