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A square wave is defined by
x(t) = 
A; 0 < t < T0/2 – A; T0/2 < t < T0
It is periodically extended outside this interval. What is the general coefficient an in the Fourier expansion of the wave?
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- 0
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2A(1 – cos nπ) nπ -
2A(1 + cos nπ) nπ -
2A(1 – cos nπ) [(n + 1)π]
Correct Option: A
Given that
| x(t) = | | – A; T0/2 < t < T0 |
where T0 is the fundamental period. If we plot this periodic square wave.
From the wave, it is clear that wave is an odd function, therefore an = 0.
Hence, alternative (A) is the correct choice.
