A periodic voltage having the Fourier series V(t) = 1 +

A periodic voltage having the Fourier series V(t) = 1 + 4 sin ωt + 2cos ωt volts is applied across a one-ohm resistor. The power dissipated in 1-ohm resistor is—

V_rms of the given Fourier series
= √1 + 4².½ + 2². ½
= √11
Power dissipated in 1 – Ω resistor

=	V²_rms	=	(√11)	= 11watt
	R		1