X(jω) = e– 2ω u(ω) then x(t)

x(t) =	1		^∞	X(jω).e^jωtdω
	2π		_{– ∞}

=	1		^∞	e^–2ω.e^jωt dω
	2π		_{– ∞}

=	1		e^{(jt – 2)ω}		^∞
	2π		(jt – 2)		₀

=	1		- 1		=	- 1
	2π		(jt – 2)			2π(2 - jt)

Hence, alternative (D) is the correct choice.