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The DTFT of the given signal
x[n] = u[n – 2] – u[n – 6]
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- e2jΩ + e3jΩ + e4jΩ + e5jΩ
- e– 2jΩ + e– 3jΩ + e– 4jΩ + e– 5jΩ
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e– 2jΩ (1 – e3jΩ) 1 – ejΩ -
e– 2jΩ (1 – e– 3jΩ) 1 – e– jΩ
Correct Option: B
so, u[n – 2] u[n – 6] u[n – 2] – u[n – 6] So, u[n – 2] – u[n – 6] = δ[n – 2] + δ[n – 3] + δ[n – 4] + δ[n – 6]
X(ejΩ) = | x[n].e–jΩn | |
= e–2jΩ + e–3jΩ + e–4jΩ + e–5jΩ