The discrete time signal x[ n] is defined by[n] =1; n =

Home » Signals and Systems » Signal and systems miscellaneous » Question

The discrete time signal x[ n] is defined by
[n] = 1; n = 1, 2
– 1; n = – 1, – 2
0; n = 0 and |n| > 2

and the time shifted signal y [n] is
y[n] = 1; n = – 1, – 2
– 1; n = – 4, – 5
0; n = – 3; n < – 5, n > – 2

then—

1. y[n] = x[n + 3]
2. y[n] = x[n – 3]
3. y[n] = x[n – 2]
4. y[n] = x[n + 2]

Correct Option: A

Given x[n] as shown below

From given waveform, we conclude that y[n] is a shifting sequence three unit left, i.e.
y[n] = x[n + 3]