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If the variance of the random variable X is σ2 x then the variance of – kx is—
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- Kσ2x
- – Kσ2x
- K2σ2x
- None of these
Correct Option: C
We know that
σ2x = E[x2] – [μx]2
= | ![]() | ∞ | x2 fx(x)dx - | ![]() | ![]() | ∞ | xfx(x)dx | ![]() | 2 | -∞ | -∞ |
Let, new variance,
σ2 x′ = | ![]() | ∞ | (– kx)2fx(x)dx - | ![]() | ![]() | ∞ | (– kx)fx(x)dx | ![]() | 2 | {∵ x′ = – kx} | -∞ | -∞ |
or
σ2 x′ = k2 | ![]() | ∞ | x2fx(x)dx - k2 | ![]() | ![]() | ∞ | xfx(x)dx | ![]() | 2 | -∞ | -∞ |
σ2 x′ = k2σ2x