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Let X and Y be has stationary independent random variables uniformly distributed in the ranges (– 1, 1) and (– 2, 1) respectively. If Z = X + Y, then the probablity that Z < – 2 is—
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- 0
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1 6 -
1 3 -
1 12
Correct Option: A
Given, random variable x lies in the range (– 1, 1) and y lies in the range (– 2, 1) i.e.
then P(z ≤ – 2) = 0