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If y(t) + ∞ y(τ) x(t – τ )dτ = S(t) + x(t) then y(t) is— 0
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- u(t)
- δ(t)
- r(t)
- 1
Correct Option: B
y(t) + | ![]() | ∞ | y(τ) x(t – τ )dτ = δ(t) + x(t) …(A) | 0 |
L.H.S. = y(t) + | ![]() | ∞ | y(τ) x(t – τ )dτ | 0 |
= y(t) + y(t) * x(t)
If we compare the equation with R.H.S part of equation (A), we conclude that
y(t) = δ(t) {∵ x(t) * δ(t) = x(0)}