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A stone is tied to a string of length l and is whirled in a vertical circle with the other end of the string as the centre. At a certain instant of time, the stone is at its lowest position and has a speed u. The magnitude of the change in velocity as it reaches a position where the string is horizontal (g being acceleration due to gravity) is
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- √2gl
- √2(u² - gl)
- √u² - gl
- u - √u² - 2gl
Correct Option: B
Wmg = ∆K
⇒ – mgl = ½ mv2 – ½ mu2
or, mv2 = m( u2 – 2gl )
or , v→ = √u² - 2gl ĵ
u→ = uî
∴ v→ - u→ = √u² - 2gl ĵ - uî
∴ | v→ - u→ | = [ (u² - 2gl) + u² ]1 / 2 = √2(u² - gl)