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A particle moves along a circle of radius 20 m with constant tangential acceleration. π
If the velocity of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is
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- 40 π m/s2
- 40 m/s2
- 640 π m/s2
- 160 π m/s2
Correct Option: B
Circumference = 2πr = 2π × | = 40 m | |
π |
Distance travelled in 2 revolutions = 2 × 40 = 80 m
Initial velocity = u = 0 Final velocity v = 80m/sec
Applying the formula, v2 = u2 + 2as
(80)2 = 02 + 2 × a × 80 ⇒ a = 40 m/sec2