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The figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then :
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- t1 = 4t2
- t1 = 2t2
- t1 = t2
- t1 > t2
Correct Option: B
According to Kepler’s law, the areal velocity of a planet around the sun always remains constant.
SCD : A1 – t1 (areal velocity constant)
SAB : A2 – t2
= | ||||
t1 | t2 |
t1 = t2. | (given A1 = 2A2) | |
A2 |
= t2. | ||
A2 |
∴ t1 = 2t2