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The period of revolution of planet A around the Sun is 8 times that of B. The distance of A from the Sun is how many times greater than that of B from the Sun?
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- 2
- 3
- 4
- 5
Correct Option: A
Let TA and TB be time period of A and B about sun.
TA = 8TB
| = 8 .....(1) | ||
| TB |
According to Kepler's Law T2 ∝ r3
| = | ⇒ |  |  | 3 | = 8 ⇒ | = 2 | |||||
| TB | (rB)3 | rB | rB |
