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An ideal gas at 27°C is compressed adiabatically to 8 of its original volume. 27 The rise in temperature is 
γ = 5 
3
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- 475°C
- 402°C
- 275°C
- 175°C
Correct Option: B
T = 27°C = 300 K
| γ = | ; V2 = | V1 ; | = | ||||
| 3 | 27 | V2 | 8 |
From adiabatic process we know that
T1 V1γ - 1 = T2 V2γ - 1
| = | | | γ - 1 | = | | | (5/3) - 1 | |||
| T1 | V2 | 8 |
| = | ⇒ T2 = | × T1 = | × 300 = 675 K | |||||
| T1 | 4 | 4 | 4 |
T2 = 675 – 273°C = 402°C
