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If the ratio of specific heat of a gas at constant pressure to that at constant volume is γ, the change in internal energy of a mass of gas, when the volume changes from V to 2V at constant pressure P, is
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R (γ - 1) - PV
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PV (γ - 1) -
γ PV (γ - 1)
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Correct Option: C
Change in internal energy is equal to work done in adiabatic system
∆W = –∆U (Expansion in the system)
| = - | (P1V1 - P2V2) | |
| γ - 1 |
| ∆U = | (P2V2 - P1V1) | |
| γ - 1 |
Here , V1 = V , V2 = 2 V
| ∴ ∆U = | [P × 2V - PV] = | ||
| 1 - γ | 1 - γ |
| ⇒ ∆U = - | ||
| γ - 1 |
