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A carnot engine having an efficiency of 1 as heat engine, is used as a refrigerator. 10
If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :-
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- 90 J
- 99 J
- 100 J
- 1 J
Correct Option: A
| Given, efficiency of engine, η = | ||
| 10 |
work done on system W = 10 J
Coefficient of performance of refrigerator
| β = | = | = | 1 - | = | = 9 | ||||||
| 10 | 10 | ||||||||||
| W | η | ||||||||||
| 10 | 10 | ||||||||||
Energy absorbed from reservoir Q2 = βw
Q2 = 9 × 10 = 90 J
