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A refrigerator works between 4°C and 30°C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is :(Take 1 cal = 4.2 joules)
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- 2.365 W
- 23.65 W
- 236.5 W
- 2365 W
Correct Option: C
Coefficient of performance of a refrigerator, β = | = | ||
W | T1 - T2 |
(Where Q2 is heat removed)
Given : T2 = 4°C = 4 + 273 = 277 k
T1 = 30°C = 30 + 273 = 303 k
β = | = | ||
W | 303 - 277 |
⇒ W = 236.5 joule
Power , P = | = | = 236.5 watt | ||
t | 1 sec |