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In a simple harmonic motion, when the displacement is one-half the amplitude, what fraction of the total energy is kinetic?
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- 0
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1 4 -
1 2 -
3 4
Correct Option: D
Total energy of particle executing S.H.M. of amplitude (A).
E = | mω2 A2 | |
2 |
K.E.of the particle = | mω2 | ![]() | A2 - | ![]() | ![]() | when x = | ![]() | ||||
2 | 4 | 2 |
= | mω2 × | A2 = | × | mω2 A2 | ||||
2 | 4 | 2 | 4 |
Clearly , | = | |||
Total energy | 4 |