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A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its
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- potential energy is 160 J
- potential energy is 100 J
- potential energy is zero
- potential energy is 120 J
Correct Option: B
Force constant k = 2 × 106 N/m
Amplitude (x) = 0.01 m
Potential Energy = | kx2 | |
2 |
= | × (2 × 106) × (0.01)2 = 100 J | |
2 |