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A plano convex lens fits exactly into a plano concave lens. Their plane surfaces are parallel to each other. If lenses are made of different materials of refractive indices µ1 and µ2 and R is the radius of curvature of the curved surface of the lenses, then the focal length of the combination is
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R 2(µ1 - µ2) -
R (µ1 - µ2) -
2R (µ2 - µ1) -
R 2(µ1 + µ2)
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Correct Option: B
= | + | ||||
f | f1 | f2 |
= (μ1 - 1) | ![]() | - | ![]() | + (μ2 - 1) | ![]() | - | ![]() | ||||
∞ | -R | ∞ | R |
= | - | ⇒ | = | ||||
R | R | f | R |
⇒ f = | ||
μ1 - μ2 |
Hence, focal length of the combination is | ||
μ1 - μ2 |